How to format a floating number to fixed width in Python

Python

Mistake producing Gemini contented Question & Answer :

However bash I format a floating figure to a fastened width with the pursuing necessities:

  1. Starring zero if n < 1
  2. Adhd trailing decimal zero(s) to enough ahead fastened width
  3. Truncate decimal digits ancient mounted width
  4. Align each decimal factors

For illustration:

% formatter thing similar '{:06}' numbers = [23.23, zero.123334987, 1, four.223, 9887.2] for figure successful numbers: mark formatter.format(figure)

The output would beryllium similar

23.2300 zero.1233 1.0000 four.2230 9887.2000 

numbers = [23.23, zero.1233, 1.zero, four.223, 9887.2] for x successful numbers: mark("{:10.4f}".format(x))

prints

23.2300 zero.1233 1.0000 four.2230 9887.2000

The format specifier wrong the curly braces follows the Python format drawstring syntax. Particularly, successful this lawsuit, it consists of the pursuing components:

  • The bare drawstring earlier the colon means “return the adjacent supplied statement to format()” – successful this lawsuit the x arsenic the lone statement.
  • The 10.4f portion last the colon is the format specification.
  • The f denotes fastened-component notation.
  • The 10 is the entire width of the tract being printed, lefted-padded by areas.
  • The four is the figure of digits last the decimal component.